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The coefficient of x in the equation x^2...

The coefficient of x in the equation `x^2+px+q=0` was wrongly written as 17 in place of 13 and the roots thus found were -2 and -15. The roots of the correct equation are (A) `15.-2` (B) `-3,-10` (C) `-13,30` (D) `4,13`

A

`-1`

B

`-3`

C

`-5`

D

`-10`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the given information and derive the correct quadratic equation. ### Step 1: Identify the incorrect quadratic equation The problem states that the coefficient of \(x\) was written as 17 instead of 13. Therefore, the incorrect quadratic equation is: \[ x^2 + 17x + q = 0 \] ### Step 2: Use the roots to find \(q\) The roots of the incorrect equation are given as -2 and -15. According to Vieta's formulas, the sum of the roots (\( \alpha + \beta \)) is equal to -p, and the product of the roots (\( \alpha \cdot \beta \)) is equal to \(q\). Calculating the product of the roots: \[ \alpha \cdot \beta = (-2) \cdot (-15) = 30 \] Thus, we have: \[ q = 30 \] ### Step 3: Write the correct quadratic equation Now that we have \(q\), we can write the correct quadratic equation with the correct coefficient of \(x\): \[ x^2 + 13x + 30 = 0 \] ### Step 4: Find the roots of the correct quadratic equation To find the roots of the correct equation \(x^2 + 13x + 30 = 0\), we can use the factorization method. We need to find two numbers that multiply to 30 and add up to 13. The numbers that satisfy this condition are 3 and 10. Thus, we can factor the equation as: \[ (x + 3)(x + 10) = 0 \] Setting each factor to zero gives us the roots: \[ x + 3 = 0 \quad \Rightarrow \quad x = -3 \] \[ x + 10 = 0 \quad \Rightarrow \quad x = -10 \] ### Conclusion The roots of the correct quadratic equation \(x^2 + 13x + 30 = 0\) are: \[ \text{Roots: } -3 \text{ and } -10 \] ### Final Answer The correct option is (B) \(-3, -10\).
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