Two boats `A` and `B` moved away from a buoy anchored in the middle of a river along the mutually perpendicular straight lines. `A` moved along the river and `B` at fight angle to it Having moves off equal distances from the boy, the boats returned. Find the ratio of the times of motion of the boats, if the velocity of each boat with respect to still water in `eta`=1.2 times greater than the velocity of water current.

Explanation

To solve the problem, we need to analyze the motion of both boats A and B, taking into account the velocity of the water current and the velocities of the boats with respect to still water.

### Step-by-Step Solution:

1. **Define Variables**:
- Let \( V_w \) be the velocity of the water current.
- Let \( V \) be the velocity of each boat with respect to still water.
- Given that \( V = \eta V_w \), where \( \eta = 1.2 \).
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