A car moving with constant acceleration covered the distance between two points `60.0 m` apart in `6.00 s.` Its speed as it passes the second point was `15.0 m//s.`
(a) What is the speed at the first point?
(b) What is the acceleration?
(c) At what prior distance from the first was the car at rest?

Answer

a. `5 m s^(-2);
b. `15 ms^(-1);
c. 22.5 m`

Explanation

`v^(2)-u^(2) =2axx180 rArr 45^(2)-u^(2) =360 a`
`v=u+at rArr 45=u+axx6`
.
Solve to get `u=15 m s^(-1)`, `a= 5 m s^(-2)`
`u^(2)=0^(2)+2ax rArr 15^(2)=0^(2) + 2 xx5x rArr `x=22.5 m`.