Home
Class 11
PHYSICS
The acceleration will be positive in ....

The acceleration will be positive in .

A

`(I) and (III)`

B

`(I) and (IV)`

C

` (II) and (IV)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
In I, slope is negative and its magnitude is decreasing with time. It means slope is increasing mumerically, So velocity is inreasing towards right and so acceleration is positve.
In IV slope is positive and its magnitude is increasing with time, So velocity is increasing towards right, and so acceleration is positive.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • KINEMATICS-1

    CENGAGE PHYSICS ENGLISH|Exercise Multiple Correct|16 Videos

  • KINEMATICS-1

    CENGAGE PHYSICS ENGLISH|Exercise Assertion-reasoning|5 Videos

  • KINEMATICS-1

    CENGAGE PHYSICS ENGLISH|Exercise Graphical Concept|17 Videos

  • GRAVITATION

    CENGAGE PHYSICS ENGLISH|Exercise INTEGER_TYPE|1 Videos

  • KINEMATICS-2

    CENGAGE PHYSICS ENGLISH|Exercise Exercise Integer|9 Videos

Similar Questions

Explore conceptually related problems

Velocity of a particle is in negative direction with constant acceleration in positive direction. Then match the following:

Which graph corresponds to an object moving with a constant negative acceleration and a positive velocity ?

Which graph corresponds to an object moving with a constant negative acceleration and a positive velocity ?

A particle starts from origin O from rest and moves with a uniform acceleration along the positive x=axis. Identify all figures that correctly represent the motion qualitatively. (a=acceleration , v=velocity, x=displacement,t=time)

A rectangular container moves with an acceleration a along the positive direction as shown in figure. The pressure at the A in excess of the atmospheric pressure p_(0) is (take rho as the density of liquid)

Assertion : In the s-t graph as shown in figure, velocity of particle is negative and acceleration is positive. Reason : Slope of s-t graph is negative and increasing in magnitude.

Fig. 2.36 shows the displacement-time graph for four bodies A, B, C and D. In each case state what information do you get about the acceleration (zero, positive or negative).

The wheel of radius R rolls wihtout slipping on horizontal rough surface and its centre O has an acceleration a_(0) in forward direction. A point P on the wheel is a distance r from O and angular position theta from horizontal. Find the angle theta for which point P can have zero acceleration in this position .

A particle is ejected from the tube at A with a velocity V at an angle theta with the verticle y-axis at a height h above the ground as shown. A strong horizontal wind gives the particle a constant horizontal acceleration a in the positive x-direction. If the particle strikes the ground at a point directly under its released position and the downward y-acceleration is taken as g then find h.

The position x of a particle varies with time t as x=at^(2)-bt^(3) .The acceleration of the particle will be zero at time t equal to

Home
Profile