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A particle P is projected with velocity ...

A particle `P` is projected with velocity `u_1` at an angle of `30^@` with the horizontal. Another particle `Q` is thrown vertically upwards with velocity `u_2` from a point vertically below the highest point of path of `P`. Determine the necessary condition for the two particles to collide at the highest point.
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Both particles collide at the highest point. It means the vertical distance travelled by both the particle will be equal, i.e., the vertical component of velocity of both particle will be equal
`u_1 sin 30^@ = u_2 rArr (u_1)/(2) = u_2 rArr u_1 = 2 u_2`.
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CENGAGE PHYSICS ENGLISH-KINEMATICS-2-Exercise 5.2
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  7. A man standing on the roof a house of height h throws one particle ver...

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  8. A staircase contains three steps each 10 cm high and 20 cm wide figure...

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  9. For a given velocity of projection from a point on the inclined plane,...

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  10. A shell is fired from a gun from the bottom of a hill along its slope....

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  11. The maximum range of a rifle bullet on the horizontal ground is 6 km. ...

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  12. A motorcycle stunt rider rides off the edge of a cliff. Just at the ed...

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  13. An object is thrown between two tall buildings 180 m from each other. ...

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  14. A fighter plane moving with a speed of 50 sqrt(2) m s^-1 upward at an ...

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  15. A bullet is fired from the bottom of the inclined plane at angle theta...

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  16. Two paper screens A and B are separated by 150 m. A bullet pierces A a...

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  17. Two stones A and B are projected simultaneously from the top of a 100 ...

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  18. On an inclined plane two particles A and B are projected with same spe...

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  19. A particle is projected with velocity v at an angle theta aith horizon...

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  20. The horizontal range (R ) of a projectile becomes (R + 2 H) from R due...

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