A body is projected horizontally from the top of a tower with initial velocity `18 m s^-1`. It hits the ground at angle `45^@`. What is the vertical component of velocity when it strikes the ground ?

Explanation

To solve the problem, we need to determine the vertical component of the velocity of a body projected horizontally from the top of a tower when it strikes the ground at an angle of 45 degrees. Here is a step-by-step solution:

### Step 1: Understand the Problem
The body is projected horizontally with an initial velocity of \( u = 18 \, \text{m/s} \). When it hits the ground, it does so at an angle of \( 45^\circ \). We need to find the vertical component of the velocity (\( V_y \)) at the moment of impact.

**Hint:** Visualize the projectile motion and the components of the velocity vector at the point of impact.

### Step 2: Analyze the Velocity Components
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