A motorcycle stunt rider rides off the edge of a cliff. Just at the edge his velocity is horizontal, with magnitude `9.0 m s^-1`. Find the motorcycle's position, distance from the edge of the cliff and velocity after `0.5 s`.

Explanation

To solve the problem of the motorcycle stunt rider riding off the edge of a cliff, we will break it down into steps to find the motorcycle's position (horizontal and vertical distances) and its velocity after 0.5 seconds.

### Step 1: Understand the Initial Conditions
- The motorcycle leaves the cliff with an initial horizontal velocity \( v_x = 9.0 \, \text{m/s} \).
- The initial vertical velocity \( v_y = 0 \, \text{m/s} \) (since the motorcycle is moving horizontally).
- The time \( t = 0.5 \, \text{s} \).

### Step 2: Calculate Horizontal Distance
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