Two guns are situated at the top of a hill firing the shots at the same speed. One gun fires the shot horizontally and other gun fires the shot at an angle of `60^@` with horizontal. Two two shots collide in air. If the time taken by horizontal shot to reach the point of collision in `3 seconds`, find the time interval between two shots.

Explanation

To solve the problem, we need to analyze the motion of the two shots fired from the guns. We will denote the initial speed of both shots as \( u \).

### Step 1: Analyze the horizontal shot
The first gun fires a shot horizontally. The time taken by this shot to reach the point of collision is given as \( t_1 = 3 \) seconds. The horizontal distance traveled by this shot can be expressed as:
\[ x_1 = u \cdot t_1 = u \cdot 3 \]
This is our **Equation 1**.
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