Home
Class 11
PHYSICS
A particle at the edge of a ratating dis...

A particle at the edge of a ratating disc speeds up at a uniform angular acceleration `prop`. If the radius of the disc is `R`, find the angular distance covered by the particle till its acquires a total acceleration `a_0`.

Text Solution

AI Generated Solution

To solve the problem, we need to find the angular distance covered by a particle at the edge of a rotating disc until it acquires a total acceleration \( a_0 \). The disc has a uniform angular acceleration \( \alpha \) and a radius \( R \). ### Step-by-Step Solution: 1. **Understand Total Acceleration**: The total acceleration \( a_0 \) of the particle in circular motion is the vector sum of tangential acceleration \( a_t \) and centripetal acceleration \( a_c \). This can be expressed as: \[ a_0^2 = a_t^2 + a_c^2 ...
Promotional Banner

Topper's Solved these Questions

  • KINEMATICS-2

    CENGAGE PHYSICS ENGLISH|Exercise Exercise Subjective|40 Videos
  • KINEMATICS-2

    CENGAGE PHYSICS ENGLISH|Exercise Exercise Single Correct|76 Videos
  • KINEMATICS-2

    CENGAGE PHYSICS ENGLISH|Exercise Exercise 5.3|12 Videos
  • KINEMATICS-1

    CENGAGE PHYSICS ENGLISH|Exercise Integer|9 Videos
  • KINETIC THEORY OF GASES

    CENGAGE PHYSICS ENGLISH|Exercise Compression|2 Videos

Similar Questions

Explore conceptually related problems

A particle of mass M and radius of gyration K is rotating with angular acceleration alpha . The torque acting on the particle is

A particle is at a distance r from the axis of rotation. A given torque tau produces some angular acceleration in it. If the mass of the particle is doubled and its distance from the axis is halved, the value of torque to produce the same angular acceleration is -

A particle is moving around a circular path with uniform angular speed (x) . The radius of the circular path is (r). The acceleration of the particle is:

Refering to v-s diagram, find: . a. Acceleration of the particle when its velocity becomes half of the initial velocity. b. Total distance covered by the particle.

A particle is revolving in a circle of radius 1 m with an angular speed of 12 rad/s. At t = 0, it was subjected to a constant angular acceleration alpha and its angular speed increased to (480/pi) rotation per minute (rpm) in 2 sec. Particle then continues to move with attained speed. Calculate (i) angular acceleration of the particle, (ii) tangential velocity of the particle as a function of time. (iii) acceleration of the particle at t = 0.5 second and at t = 3 second (iv) angular displacement at t = 3 second.

If a tangential force mg is applied to a disc of mass m and radius r, the angular acceleration produced in it is?

A coin is placed at the edge of a horizontal disc rotating about a vertical axis through its axis with a uniform angular speed 2 rad s^(-1) . The radius of the disc is 50 cm. Find the minimum coefficient of friction between disc and coin so that the coin does not slip. (Take g = 10 m//s^(2) )

In a non - uniform circular motaion the ratio of tangential to radial acceleration is (where, r= radius of circle, v= speed of the particle, alpha= angular acceleration)

The radius of gyration of a uniform disc about a line perpendicular to the disc equals to its radius. Find the distance of the line from the centre.

A disc initially at rest , is rotated about its axis with uniform angular acceleration . In the first 2 s, it rotates an angle theta . In the next 2s, the disc rotates through an angle