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Two blocks m(1) and m(2) are acted upon...

Two blocks `m_(1)` and `m_(2) ` are acted upon by the forces `F_(1)` and `F_(2) ` as shown in figure . If no relative sliding between is smooth , find the static friction between the blocks. Make necessary assumptions and discuss different cases.

Text Solution

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As there is no sliding between the blocks , the friction will be static. Assuming the frictional forces on `m_(1)` as `f(larr)` and `m_(2)` as `f(rarr )` we have drawn the `FBD` without normal reactions and weight .

Referring to `FBD` as shown in fig we have the following equation of motion :
For `m_(1): F_(1) -f = m_(1)a_(1)` ...(i)
For `m_(2) : F_(2) +f =m_(2)a_(2)` ...(ii)
Since the friction is static `a_(1) = a_(2)`
Substituting Eq (i) `a_(1)`from Eq `a_(1)`(ii) in (iii) we have
`(F_(1) - f)/(m_(1)) = (F_(2) - f)/(m_(2))`
This gives `f = (m_(2)F_(1) - m_(1)F_(2))/(m_(1) + m_(2)`
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