Two block of masses `M_(1)` and, `M_(2)` are connected with a string which passed over a smooth pulley . The mass `M_(1)` is placed on a tough inclined plane as shown in figure .The coefficient of friction between and block and the inclined plane is `mu` what should be the minimum mass `M_(2)` so that the block `M_(1)` slides upwards?

Options

A. `M_(2) = M_(1) (sin theta + mu cos theta)`
B. `M_(2) = M_(1) (sin theta - mu cos theta)`
C. `M_(2) = (M_(1))/(sin theta + mu cos theta)`
D. `M_(2) = (M_(1))/(sin theta - mu cos theta)`

Answer

a

Explanation

For upward accelerationof `M_(1)`:
`M_(2)g geM_(1) g sin theta + mu M_(1) g cos theta`
`rArr (M_(2))_(max) = M_(1) (sin theta + mu cos theta)`