In the figure shown `q` is in coulomb and t in second. At time `t=1 s`

Options

A. Car A completes its journey before car B
B. Both cars complete their journey in same time
C. Velocity of car A is greater than that of car B
D. Car B of car A is journey before carA

Answer

d

Explanation

Maximum velocity for car A
`v_(A, max)= sqrt(mu gr) = sqrt(0.1 xx 10 xx 100) = 10 ms^(-1)`
`v_(B, max) = sqrt(mu_(B)gR_(B)) = sqrt(0.2 xx 10 xx 200) = 20 ms^(-1)`
Time taken by car A
`t_(A) = (200 pi + pi. 100)/(100) = 3 pi s`
`t_(B) = (200 + pi xx 200)/(20) = 2 pi s`