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Block A of mass m and block B of mass `2m` are placed on a fixed traingular wedge by means of a massless inextensible string and a frictionless pulley as shown in figure The wedge is inclined at `45^(@)`to the horizontal on both sides .The coefficient of friction between blocks A and the wedge is `2//3` and that between block B and is released from rest find the following

The magnitude and direction of the force of friction acting on A are

A

`mg` down the plane

B

`(mg)/(2)`up the plane

C

`(mg)/(sqrt(2))`,up the plane

D

`(mg)/(3sqrt(2))`down the plane

Text Solution

Verified by Experts

The correct Answer is:
D

`T = mg sin 45^(@) +f_(1) rArr f_(1) = (mg)/(3sqrt(2))`
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CENGAGE PHYSICS ENGLISH-NEWTON'S LAWS OF MOTION 2-Linked Comprehension
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