A block of mass kg lies on a horizontal surface in a truck· The coefficient of stalk friction between the block and the surface is 0.6. If the acceleration of the truck is `5ms^(-2)`. The frictional force acting on the block is

Answer

NA

Explanation

Mathed 1 The maximum friction force that can act on the mass of `1kg` will be

`mu N = mu mg = 0.6 xx 1 xx 9.8 = 5.88N `
The track is acceleration at `5ms^(-2)`The perndo force acting on the mass as seen by the observer on the track is
`m xx a = 1xx 5 = 5N`
The frictional force will try to opposite the movement of the mass by this force Therefore the frictional force acting will be `5N`
Method 2 As seen by the observebed on the ground the frictional force is responcible to move the mass with an acceleration of `5ms^(-2)` Therefore frictional force is
`m xx a = 1 xx 5= 5N`