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Two unequal masses are tied together wit...

Two unequal masses are tied together with a cord with a compressed spring in between. The cord is burned.
Which of the following energies is conserved for the system?

A

(a) Kinetic energy

B

(b) Potential energy

C

(c) Mechanical energy

D

(d) None of these

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The correct Answer is:
To solve the problem, we need to analyze the situation involving two unequal masses tied together with a cord and a compressed spring in between them. When the cord is burned, we need to determine which type of energy is conserved in the system. ### Step-by-Step Solution: 1. **Understand the Initial State**: - Initially, the two masses \( m_1 \) and \( m_2 \) are at rest, meaning their kinetic energy is zero. - The spring is compressed, which means there is potential energy stored in the spring, given by the formula \( PE = \frac{1}{2} k x^2 \), where \( k \) is the spring constant and \( x \) is the compression distance. **Hint**: Identify the initial energies in the system before any action takes place. 2. **Action of Burning the Cord**: - When the cord is burned, the spring will decompress, causing the two masses to move apart. - As the spring decompresses, the potential energy stored in the spring will convert into kinetic energy of the two masses. **Hint**: Consider the transformation of energy types when the cord is burned. 3. **Kinetic Energy After the Release**: - After the cord is burned, the masses will have some kinetic energy as they move apart. The kinetic energy of the system can be expressed as: \[ KE = \frac{1}{2} m_1 v_1^2 + \frac{1}{2} m_2 v_2^2 \] - Here, \( v_1 \) and \( v_2 \) are the velocities of masses \( m_1 \) and \( m_2 \) respectively. **Hint**: Remember that kinetic energy will increase as the spring releases its stored energy. 4. **Conservation of Energy**: - The total mechanical energy of the system is the sum of the kinetic energy and the potential energy. Initially, the total mechanical energy is purely potential energy (from the spring). - After the cord is burned, the potential energy decreases as the spring decompresses, while the kinetic energy of the masses increases. - Since there are no external forces acting on the system (assuming no friction or air resistance), the total mechanical energy is conserved. **Hint**: Think about the principle of conservation of energy in a closed system. 5. **Conclusion**: - The potential energy of the spring is converted into kinetic energy of the masses, but the total mechanical energy remains constant throughout the process. - Therefore, the correct answer is that **mechanical energy is conserved** in the system. ### Final Answer: The energy that is conserved for the system is **mechanical energy**.

To solve the problem, we need to analyze the situation involving two unequal masses tied together with a cord and a compressed spring in between them. When the cord is burned, we need to determine which type of energy is conserved in the system. ### Step-by-Step Solution: 1. **Understand the Initial State**: - Initially, the two masses \( m_1 \) and \( m_2 \) are at rest, meaning their kinetic energy is zero. - The spring is compressed, which means there is potential energy stored in the spring, given by the formula \( PE = \frac{1}{2} k x^2 \), where \( k \) is the spring constant and \( x \) is the compression distance. ...
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