A pendulum bob swings along a circular path on a smooth inclined plane as shown in figure, where `m=3kg`, `l=0.75m`, `theta=37^@`. At the lowest point of the circle the tension in the string is `T=274N`. Take `g=10ms^-2`.

The speed of the bob at the lowest point is

Options

A. (a) `9.2ms^-1`
B. (b) `9ms^-1`
C. (c) `6.5ms^-1`
D. (d) `8ms^-1`

Answer

D

Explanation

At the lowest point: `T_L=mg sin 37^@+(mv^2)/(l)`
`implies274=3xx10xx3/5+(3V_L^2)/(0.75)impliesv_L=8ms^-1`