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A pendulum bob swings along a circular p...

A pendulum bob swings along a circular path on a smooth inclined plane as shown in figure, where `m=3kg`, `l=0.75m`, `theta=37^@`. At the lowest point of the circle the tension in the string is `T=274N`. Take `g=10ms^-2`.

The speed of the bob at the highest point on the circle is

A

(a) `sqrt46ms^-1`

B

(b) `sqrt26ms^-1`

C

(c) `sqrt52ms^-1`

D

(d) `sqrt35ms^-1`

Text Solution

Verified by Experts

The correct Answer is:
A
Let the speed at the highest point be `v_H`.
`1/2mv_H^2+mg2lsin 37^@=1/2mv_L^2impliesv_H=sqrt(46)ms^-1`
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