The figure shows the variation of potential energy of a particle as a function pf x, the x-coordination of the region. It has been assumed that potential energy depends only on `x`. For all other values `x, U` is zero. i.e. for` x lt - 10` and `x gt 15, U = 0`.

If total mechanical energy of the particle is `25J`, then it can found in the region

Options

A. (a) `-10ltxlt-5` and `6ltxlt15`
B. (b) `-10ltxlt0` and `6ltxlt10`
C. (c) `-5ltxlt6`
D. (d) `-10ltxlt10`

Answer

A

Explanation

The concept used in solving these questions is that kinetic energy can never be negative. It would always be non-negative.
Total mechanical energy `=KE+U`
Here if `E=25J`, then `K=25-U`
For K to be non-negative, `Ult25J`, which is the case for `-ooltxlarr5` and `5ltxltoo`.