A particle of mass m is made to move with uniform speed v along the perimeter of a regular polygon of 2 n sides . The magnitude of impulse applied at each corner of the polygon is

Answer

`2musin((pi(/n)`

Explanation

`theta=(2pi)/n` impulse `=` change in momentum

`sqrt((mu)^(2)+(mu)^(2)-2(mu)costheta)`
`=2musin(theta/2)=2musin(pi/n)`