A sphere is moving with velocity vector ...

A sphere is moving with velocity vector `2hati+2hatj` immediately before it hits a vertical wall. The wall is parallel to `hatj` and the coefficient of restitution of the sphere and the wall is `e=1/2`. Find the velocity of the sphere after it hits the wall?

`hati-hatj`

`-hati+2hatj`

`-hati-hatj`

`2hati-hatj`

Text Solution

Verified by Experts

The correct Answer is:

`hatj` component i.e., component of velocity parallel to wall remains unchanged while `hatj` component will become `(-1/2)(2hati)or -hati`. Therefore velocity of the sphere after it hits the wall `-hati+2hatj`.

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