A particle of mass `m` moving with a velocity `u` makes an elastic one-dimensional collision with a stationary particle of mass `m` establishing a contact with it for extermely small time. `T`. Their force of contact increases from zero to `F_0` linearly in time `T//4`, remains constant for a further time `T//2` and decreases linearly from `F_0` to zero in further time `T//4` as shown. The magnitude possessed by `F_0` is.
.

Options

A. `("mu")/T`
B. `(2"mu")/T`
C. `(4"mu")/(3T)`
D. `(3"mu")/(4T)`

Answer

C

Explanation

Impulse `=` area of tapezium,
`=1/2(T+T/2)F_(0)=(3TF_(0))/4`
According to impulse momentum theorem.
Impulse change in momentum
`implies (3TF_(0))/4="mu"impliesF_(0)=(4"mu")/(3T)`