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A 3000 kg space probe is moving in a gra...

A `3000 kg` space probe is moving in a gravity free space at a constant velocity of `300 m//s`. To change the direction of space probe, rockets have been fired in a direction perpendicular to the direction of initial motion of the space probe, the rocket firing exerts a thrust of `4000 N` for `225 s`. The space probe will turn by an angle of (neglect the mass of the rockets fired)

A

`30^(@)`

B

`60^(@)`

C

`45^(@)`

D

`37^(@)`

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The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Identify the initial momentum of the space probe The initial momentum (P_initial) of the space probe can be calculated using the formula: \[ P_{\text{initial}} = m \cdot v_i \] where: - \( m = 3000 \, \text{kg} \) (mass of the space probe) - \( v_i = 300 \, \text{m/s} \) (initial velocity) Calculating: \[ P_{\text{initial}} = 3000 \, \text{kg} \cdot 300 \, \text{m/s} = 900000 \, \text{kg m/s} \] ### Step 2: Calculate the change in momentum due to the thrust The change in momentum (P_thrust) caused by the thrust of the rockets can be calculated using: \[ P_{\text{thrust}} = F \cdot t \] where: - \( F = 4000 \, \text{N} \) (thrust) - \( t = 225 \, \text{s} \) (time duration) Calculating: \[ P_{\text{thrust}} = 4000 \, \text{N} \cdot 225 \, \text{s} = 900000 \, \text{N s} \] ### Step 3: Apply conservation of momentum in the y-direction When the rockets are fired, the momentum in the y-direction (P_y) will equal the change in momentum due to the thrust: \[ P_y = P_{\text{thrust}} = 900000 \, \text{kg m/s} \] ### Step 4: Apply conservation of momentum in the x-direction The momentum in the x-direction (P_x) remains unchanged since there are no external forces acting in that direction: \[ P_x = P_{\text{initial}} = 900000 \, \text{kg m/s} \] ### Step 5: Relate the momentum components to the angle θ The momentum components can be expressed in terms of the angle θ: - In the y-direction: \( P_y = P \sin(\theta) \) - In the x-direction: \( P_x = P \cos(\theta) \) Where \( P \) is the resultant momentum after the thrust is applied. ### Step 6: Set up the equations From the conservation of momentum: 1. \( P \sin(\theta) = 900000 \) 2. \( P \cos(\theta) = 900000 \) ### Step 7: Divide the equations to find θ Dividing the first equation by the second: \[ \frac{P \sin(\theta)}{P \cos(\theta)} = \frac{900000}{900000} \] This simplifies to: \[ \tan(\theta) = 1 \] ### Step 8: Solve for θ Taking the arctan of both sides: \[ \theta = \arctan(1) = 45^\circ \] ### Final Answer The space probe will turn by an angle of \( 45^\circ \). ---

To solve the problem, we will follow these steps: ### Step 1: Identify the initial momentum of the space probe The initial momentum (P_initial) of the space probe can be calculated using the formula: \[ P_{\text{initial}} = m \cdot v_i \] where: - \( m = 3000 \, \text{kg} \) (mass of the space probe) - \( v_i = 300 \, \text{m/s} \) (initial velocity) ...
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