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A ball is projected in a direction incli...

A ball is projected in a direction inclined to the vertical and bounces on a smooth horizontal plane. The range of one rebound is `R`. If the coefficient of restitution is `e`, then range of the next rebound is

A

`R'=eR`

B

`R'=e^(2)R`

C

`R'=R/e`

D

R'=R`

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The correct Answer is:
To solve the problem, we need to determine the range of the next rebound of a ball that has already bounced once, given the initial range \( R \) and the coefficient of restitution \( e \). ### Step-by-Step Solution: 1. **Understanding the Initial Conditions**: - A ball is projected at an angle \( \theta \) to the horizontal. - The range of the first rebound is given as \( R \). - The coefficient of restitution \( e \) affects the vertical component of the velocity after the bounce. 2. **Range Formula**: - The range \( R \) of a projectile is given by the formula: \[ R = \frac{2u^2 \sin \theta \cos \theta}{g} \] - Here, \( u \) is the initial velocity, \( g \) is the acceleration due to gravity, and \( \theta \) is the angle of projection. 3. **Components of Velocity**: - The horizontal component of the initial velocity is: \[ u_x = u \cos \theta \] - The vertical component of the initial velocity is: \[ u_y = u \sin \theta \] 4. **After the First Bounce**: - Upon bouncing, the horizontal component of the velocity remains unchanged: \[ u_x' = u \cos \theta \] - The vertical component of the velocity after the bounce is reduced by the coefficient of restitution: \[ u_y' = e \cdot (u \sin \theta) \] 5. **Calculating the Range of the Next Rebound**: - The range \( R' \) for the next rebound can be calculated using the new vertical component: \[ R' = \frac{2 (u_x')^2 \sin \theta \cos \theta}{g} \] - Substituting \( u_x' \) and \( u_y' \): \[ R' = \frac{2 (u \cos \theta)^2 (e \cdot (u \sin \theta)) \cos \theta}{g} \] - This simplifies to: \[ R' = \frac{2 (u^2 \cos^2 \theta) (e \cdot (u \sin \theta))}{g} \] - Rearranging gives: \[ R' = e \cdot R \] 6. **Final Result**: - Therefore, the range of the next rebound is: \[ R' = eR \] ### Summary: The range of the next rebound is directly proportional to the range of the first rebound multiplied by the coefficient of restitution \( e \).

To solve the problem, we need to determine the range of the next rebound of a ball that has already bounced once, given the initial range \( R \) and the coefficient of restitution \( e \). ### Step-by-Step Solution: 1. **Understanding the Initial Conditions**: - A ball is projected at an angle \( \theta \) to the horizontal. - The range of the first rebound is given as \( R \). - The coefficient of restitution \( e \) affects the vertical component of the velocity after the bounce. ...
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