Three identical thin rods, each of mass `m` and length `l`, are joined to form an equilateral triangular frame. Find the moment of inertia of the frame about an axis parallel to tis one side and passing through the opposite vertex. Also find its radius of gyration about the given axis.

Explanation

To find the moment of inertia of the equilateral triangular frame formed by three identical thin rods about an axis parallel to one side and passing through the opposite vertex, we can follow these steps:

### Step 1: Understand the Geometry
We have an equilateral triangle formed by three rods, each of mass \( m \) and length \( l \). We need to find the moment of inertia about an axis parallel to one side (let's say side BC) and passing through the opposite vertex (point A).

### Step 2: Identify the Moment of Inertia of Each Rod
1. **For Rod AB**: The moment of inertia about the axis through A (which is parallel to BC) can be calculated using the parallel axis theorem. The distance from the axis to the center of mass of rod AB is \( \frac{l}{2} \) (since the center of mass of a rod is at its midpoint).
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