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The weight of an object on the surface o...

The weight of an object on the surface of the Earth is 40 N. Its weight at a height equal to the radius of the Earth is

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When the car is on the point of rolling over, the normal force on its inside wheels is zero.
`sumF_(y)=ma_(y):n-mg=0`
`sumF_(x)=ma_(x):f=(mv^(2))/R`
Take torque about the centre of mass
`fh-n d/2=0`
Then by substitution
`(mv_("max")^(2))/Rh-(mgd)/2=0implies v_("max")=sqrt((gdR)/(2h))`
A wider whelbase (larger `d`) and a lower centre of mass (smaller `h`) will refuce the risk of rollover.
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