Home
Class 11
PHYSICS
Find a(C) and alpha of the smooth rod of...

Find `a_(C)` and `alpha` of the smooth rod of mass `m` and length `l`.

Text Solution

Verified by Experts

Force equation
`F-2F=maimpliesa=-F/m`
Hence `veca=-F/mhati`
Torque equation about centre of mass
`F.l/2+(2/3-l/2)=l_(C)alpha`
`F.l/2+Fl/6=(ml^(2))/12.alpha`
`3/2Fl=(ml^(2))/12.alphaimplies (8F)/(ml)`
Hence `vecalpha=(8F).(ml) hatk`
Promotional Banner

Topper's Solved these Questions

  • RIGID BODY DYNAMICS 1

    CENGAGE PHYSICS ENGLISH|Exercise Subjective|13 Videos

  • RIGID BODY DYNAMICS 1

    CENGAGE PHYSICS ENGLISH|Exercise Single Correct|97 Videos

  • RIGID BODY DYNAMICS 1

    CENGAGE PHYSICS ENGLISH|Exercise Exercise 2.3|15 Videos

  • PROPERTIES OF SOLIDS AND FLUIDS

    CENGAGE PHYSICS ENGLISH|Exercise INTEGER_TYPE|2 Videos

  • RIGID BODY DYNAMICS 2

    CENGAGE PHYSICS ENGLISH|Exercise Interger|2 Videos

Similar Questions

Explore conceptually related problems

Find alpha, a_(Q) and the point of zero acceleration when the horizontal force F acts on the smooth rod of mass m and length l which is kept on a horizontal surface.

A ball of mass m collides elastically with a smooth hanging rod of mass M and length l . a. If M=3m find the value of b for which no horizontal reaction occurs at the pivot. b. For what value of m//M the ball falls dead just after the collision assuminng e=(1/2) ?

find the radius of gyration of a rod of mass m and length 2l about an axis passing through one of its ends and perpendicular to its length.

ABC is a triangular framwork of three uniform rods each of mass m and length 2l . It is free to rotate in its own plane about a smooth horizontal axis through A which is perpendicular to ABC. If it is released from rest when AB is horizontal and C is above AB. Find the maximum velocity of C in the subsequent motion.

The radius of gyration of a uniform rod of mass m and length l about an axis perpendicular to its length and at distance l/4 from its centre will be

Moment of inertia of a thin rod of mass m and length l about an axis passing through a point l/4 from one end and perpendicular to the rod is

Moment of inertia of a uniform rod of mass m and length l is (7)/(12)ml^(2) about a line perpendicular to the rod. Find the distance of this line from the middle point of the rod.

Find the moment of inertia of the rod AB about an axis yy as shown in figure. Mass of the rod is m and length is l.

Calculate the force exerted by point mass m on rod of uniformly distributed mass M and length l (Placed as shown in figure) .

Calculate the moment of inertia of a uniform rod of mass M and length l about an axis passing through an end and perpendicular to the rod. The rod can be divided into a number of mass elements along the length of the rod.