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The moment of inertia of a door of mass ...

The moment of inertia of a door of mass `m`, length `2 l` and width `l` about its longer side is.

A

`(11ml^(2))/24`

B

`(5ml^(2))/24`

C

`(ml^(2))/3`

D

none of these

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The correct Answer is:
To find the moment of inertia of a door of mass \( m \), length \( 2l \), and width \( l \) about its longer side, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Geometry**: - The door has a mass \( m \), length \( 2l \), and width \( l \). - We will calculate the moment of inertia about the longer side, which is along the length \( 2l \). 2. **Set Up the Coordinate System**: - Place the door in the coordinate system such that the longer side (length \( 2l \)) is along the x-axis. - The center of the door will be at the origin, so the edges will be at \( -l \) and \( l \) along the x-axis, and the width \( l \) extends along the y-axis from \( -\frac{l}{2} \) to \( \frac{l}{2} \). 3. **Consider an Elemental Strip**: - Take a vertical strip of width \( dx \) at a distance \( x \) from the origin. The height of this strip is \( l \). - The elemental mass \( dm \) of this strip can be expressed as: \[ dm = \frac{m}{\text{Area}} \cdot \text{Area of strip} = \frac{m}{2l \cdot l} \cdot (l \cdot dx) = \frac{m}{2l} \cdot dx \] 4. **Calculate the Moment of Inertia of the Strip**: - The moment of inertia \( dI \) of this elemental strip about the axis (longer side) is given by: \[ dI = dm \cdot x^2 = \left(\frac{m}{2l} \cdot dx\right) \cdot x^2 \] 5. **Integrate to Find Total Moment of Inertia**: - The total moment of inertia \( I \) is obtained by integrating \( dI \) from \( -l \) to \( l \): \[ I = \int_{-l}^{l} dI = \int_{-l}^{l} \left(\frac{m}{2l} \cdot x^2 \cdot dx\right) \] - Factor out the constant: \[ I = \frac{m}{2l} \int_{-l}^{l} x^2 \, dx \] 6. **Evaluate the Integral**: - The integral \( \int_{-l}^{l} x^2 \, dx \) can be calculated as: \[ \int x^2 \, dx = \frac{x^3}{3} \Big|_{-l}^{l} = \frac{l^3}{3} - \left(-\frac{l^3}{3}\right) = \frac{2l^3}{3} \] - Substitute this back into the equation for \( I \): \[ I = \frac{m}{2l} \cdot \frac{2l^3}{3} = \frac{ml^2}{3} \] 7. **Final Result**: - The moment of inertia of the door about its longer side is: \[ I = \frac{ml^2}{3} \]

To find the moment of inertia of a door of mass \( m \), length \( 2l \), and width \( l \) about its longer side, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Geometry**: - The door has a mass \( m \), length \( 2l \), and width \( l \). - We will calculate the moment of inertia about the longer side, which is along the length \( 2l \). ...
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