In Fig, the bar is uniform and weighing `500 N`. How large must `W` be if `T_(1)` and `T_(2)` are to be equal?

Options

A. `500N`
B. `300N`
C. `750N`
D. `1500N`

Answer

D

Explanation

Taking torque about the attachmet point for `W` get
`-T_(1)(0.4L)+T_(2)(0.3L)+500(0.2L)=0`
`T=1000N`, were `T_(1)=T_(2)=T`
`SigmaF_(y)=0gt2T-W-500=0`
`implies W=1500N`