A uniform rod of length l is placed symm...

A uniform rod of length `l` is placed symmetrically on two walls as shown in Fig. The rod is in equilibrium. If `N_(1)` and `N_(2)` are the normal forces exerted by the walls on the rod, then

`N_(1)gtN_(2)`

`N_(1)ltN_(2)`

`N_(1)=N_(2)`

`N_(1)` and `N_(2)` would be in the vertical directions

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The correct Answer is:

As rod is in equlibrium. The torque of all the forces about the `CM` is zero. `N_(1) l/4 = N_(2) l/4 implies N_(1)=N_(2)`

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