A uniform bar `AB` of mass `m` and a ball of the same mass are released from rest from the same horizontal position. The bar is hinged at end `A`. There is gravity downwards. What is the distance of the point from point `B` that has the same acceleration as the ball, immediately after release?

Options

A. `(2L)/3`
B. `L/3`
C. `L/2`
D. `(3L)/4`

Answer

B

Explanation

`mgL/2=1/3mL^(2)alpha`
`alpha=(3g)/(2L)`
`and alphax=g (3g)/(2L)x=g`

`x=(2L)/3`
distance from `B:L-x=L/3`