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A disc of radius R rolls without slippin...

A disc of radius R rolls without slipping at spped v along positve x-axis. Velocity of point P at the instant shown in figure is

A

`(vsqrt(x^(2)+y^(2)))/(R`

B

`(vsqrt(x^(2)+(y+R)^(2)))/R`

C

`(vsqrt(v^(2)+(y-R)^(2)))/R`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
`omega=v/R`, Distance of `P` from origin
`r=sqrt(x^(2)+y^(2))`
origin is instantaneous centre of rotatio. So,
`v_(P)=omegar=(vsqrt(x^(2)+y^(2)))/R`
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