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Four spheres A, B, C, D, each of mass m ...

Four spheres A, B, C, D, each of mass m and diameter 2 a are placed with their centres at die four corners of a square of side b. What is the moment of inertia of the system about any side of the square ?

Text Solution

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The correct Answer is:
9

`I=(2/5MR^(2))2+(2/5MR^(2)+Mx^(2))2`
`(2/5MR^(2))2+(2/5MR^(2))=(Mx^(2))2`
`=4(2/5MR^(2))+2Mx^(2)=8/5MR^(2)+2mx^(2)`
`=[8/5xx0.5xx(sqrt(5)/2)^(2)+2xx(0.5)xx84xx2)]10^-4`
`=[5/5+8]xx10^(-4)=9xx10^(-4)=Nx10^(-4)`
So, `N=9`
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