The current voltage graphs for a given metalic wire two different temperature `T_1` and `T_2` are shown in figure The temperature `T_2` is greater than `T_1.` Is this statement true or false?

Explanation

We know R = V/I and slope of IV
curve is I/R.
or `R = (1)/(slope)`
Sine the slop of `OT_2` is smaller
then `OT_1,` the resistance of wire
at `T_2` is greater then that at `T_1`
as resistance increase with
temperature, so temperature `T_2`
is greater then `T_1.`