In the nuclear process , `C_(6)^(11) rarr _(2)B^(11) + beta^(+) + X , X` stands for…….

Explanation

To solve the question regarding the nuclear process \( C_{6}^{11} \rightarrow B_{5}^{11} + \beta^{+} + X \), we need to identify what \( X \) represents in this decay process. Here’s a step-by-step breakdown of the solution:

### Step 1: Understand the Decay Process
In the given decay process, carbon-11 (\( C_{6}^{11} \)) undergoes beta plus (\( \beta^{+} \)) decay. In beta plus decay, a proton in the nucleus is transformed into a neutron, emitting a positron (the \( \beta^{+} \) particle) and a neutrino.

### Step 2: Analyze the Changes in Atomic and Mass Numbers
- The atomic number of carbon (\( C \)) is 6. When it decays to boron (\( B \)), the atomic number decreases by 1 (from 6 to 5).
- The mass number remains the same during this decay process, which is 11.
...