The rms value of an AC of 50Hz is 10 A. the time taken by an alternating current in reaching from zero to maximum value and the peak value of current will be

Options

A. `2xx10^(-2) s and 14.14 A`
B. `1xx10^(-2) s and 7.07 A`
C. `5xx10^(-3) s and 7.07 A`
D. `5xx10^(-3) s and 14.14 A`

Answer

D

Explanation

Time for reaching maximum of peak value form 0
`(T)/(4) =(1)/(4)xx(1)/(500 s)=1/200 s =5xx10^(-3)s`
`(I_0)=10 sqrt(2) A =14.14 A`