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A capacitor of capacitance 1muF is charg...

A capacitor of capacitance 1`mu`F is charged to a potential of 1V . It is connected in parallel to an inductor of inductance `10^(-3)`H. The maximum current that will flow in the circuit has the value

A

(A) `sqrt(1000)mA`

B

(B) `1mA`

C

(C) `1(mu)A`

D

(D) `1000 mA`

Text Solution

Verified by Experts

The correct Answer is:
A
Change on the capacitor, ltbRgt `(q_0)=CV = 1xx10^(-6) xx1 =10^(-6)C`
or `(I_0) = omega (q_0)=`maximum current
Now `omega =(1)/(sqrt(LC))=(1)/(sqrt(10^(-9)) =(10^(9))^(1//2)`
`:. I_0=(10^(9))^(1//2) xx(1 xx 10^(-6)) = sqrt(10^(-3)) A=sqrt(1000)mA`.
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