In a series LCR circuit the voltage across the resistance, capacitance and inductance is 10V each. If the capacitance is short circuited, the voltage across the inductance will be

Options

A. (A) 10 V
B. (B) `10//(sqrt(2))V`
C. (C) `(10//3)V`
D. (D) `20 V`

Answer

B

Explanation

Here `R=X_(L) =X_(C ) (: "Voltage across them is same")`
When capacitor is short circuited
`I=(10)/((R^(2)+x_(L)^(2))^(1//2))=(10)/(sqrt(2)R)`
`:.` Potential drop across inductance `=IX_(L) =IR = 10 sqrt(2)V`.