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An alternating voltage E = 200sqrt 2sin(...

An alternating voltage E = 200`sqrt 2`sin(100t) is connected to a `mu`F capacitor through an AC ammeter. The reading of the ammeter shall be

A

`10 mA`

B

`5 mA`

C

`5 sqrt(2)mA`

D

`10 sqrt(2)mA`

Text Solution

Verified by Experts

The correct Answer is:
B
`X_(C) = 1/(omega C) =(1)/(100 xx 10 ^(-6)) = 10^(4) Omega`
so, ` I_(rms) = (E_(rms))/(Z) = (50 sqrt(2))/(sqrt(2) xx 10^(4)) = 5 mA`.
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