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When an AC source of emf E=E(0)sin(100t)...

When an AC source of emf `E=E_(0)sin(100t)` is connected across a circuit, the phase difference between the emf E and the current I is observed be `pi/4`, as shown in the figure. If the circuit consists possibly only of R-C or R-L in series, which of the following combinations is possible?

A

`R=1 kOmega, C=10 (mu)F`

B

`R=1 kOmega, C=1(mu)F`

C

`R=1 kOmega,L=10 (mu)F`

D

`R=1 kOmega, L=1 (mu)F`

Text Solution

Verified by Experts

The correct Answer is:
A
Current leads emf so the circuit is R-C
`tan (phi) =X_(C )//R, phi=45^(@), R=1000 Omega , omega=100`
since `tan 45^(@) =(1)/(omega CR), so, C=10(mu)F`.
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