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A current source sends a current I=(i0) ...

A current source sends a current `I=(i_0) cos (omegat)`, When connected across an unknown load, it gives a voltages output of `v=v_(0)sin [omega t+(pi//4)]` across that load. Then the voltage across the current source may bebroaught in phase with the current through it by

A

Connecting an inductor in series with the load

B

Connecting an capactor in series with the load

C

Connecting an inductor in parallel with the load

D

Connecting an capactor in parallel with the load

Text Solution

Verified by Experts

The correct Answer is:
A
`v=(v_0) sin [ omega t+(pi//4)]=(v_0) cis [0=omega t -(pi//4)]`
Since V lags currents an inductor can bring it in phases with currents.
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