Steam at `100^@C` is passed into a calorimeter of water equivalent 10 g containing 74 cc of water and 10 g of ice at `0^@C`. If the temperature of the calorimeter and its contents rises to `5^@C`, calculate the amount of steam passed. Latent heat of steam`=540 kcal//kg`, latent heat of fusion`=80 kcal//kg`.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Calculate the heat required to convert ice to water
We have 10 g of ice at 0°C. The latent heat of fusion of ice is given as 80 kcal/kg, which can be converted to calories as follows:

\[ \text{Latent heat of fusion} = 80 \text{ kcal/kg} = 80 \times 1000 \text{ cal/kg} = 80000 \text{ cal/kg} = 80 \text{ cal/g} \]
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