An electric heater whose power is 54 W is immersed in `650cm^3` water in a calorimeter. In 3 min the water is heated by `3.4^@C`. What part of the energy of the heater passes out of the calorimeter in the form of radiant energy?

Explanation

To solve the problem step by step, we will follow these calculations:

### Step 1: Calculate the energy supplied by the electric heater (Eh)
The power of the electric heater is given as 54 W (watts). The time for which the heater operates is 3 minutes. We need to convert this time into seconds for our calculations.

\[ \text{Time in seconds} = 3 \text{ minutes} \times 60 \text{ seconds/minute} = 180 \text{ seconds} \]
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