An earthen pitcher loses 1 g of water per minute due to evaporation. If the water equivalent of pitcher is 0.5 kg and the pitcher contains 9.5 kg of water, calculate the time required for the water in the pitcher to cool to `28^@C` from its original temperature of `30^@C` Neglect radiation effect. Latent heat of vapourization of water in this range of temperature is 580 cal/g and specific heat of water is `1 kcal//gC^(@)`

Explanation

To solve the problem step by step, we will follow the principles of calorimetry and the formulas related to heat transfer and evaporation.

### Step 1: Calculate the heat lost by the water and the pitcher

We need to calculate the total heat lost by the water and the pitcher as the temperature drops from 30°C to 28°C.

**Formula:**
\[ Q = ms\Delta T + Wc\Delta T \]
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