The oxidation number of `S` in `S_(8),S_(2)F_(2)`, and `H_(2)S`, respectively, are

Options

A. `0,+1` and `-2`
B. `+2, +1` and `-2`
C. `0,+1` and `+2`
D. `-2, +1` and `-2`

Explanation

To find the oxidation number of sulfur (S) in the compounds \( S_8 \), \( S_2F_2 \), and \( H_2S \), we will analyze each compound step by step.

### Step 1: Determine the oxidation number of sulfur in \( S_8 \)

1. **Identify the compound**: \( S_8 \) is a molecular form of sulfur.
2. **Assign oxidation number**: In elemental form, the oxidation number of any element is 0.
3. **Conclusion**: Therefore, the oxidation number of sulfur in \( S_8 \) is **0**.

### Step 2: Determine the oxidation number of sulfur in \( S_2F_2 \)

1. **Identify the compound**: \( S_2F_2 \) consists of sulfur and fluorine.
2. **Assign known oxidation number**: Fluorine (F) has an oxidation number of -1.
3. **Set up the equation**: Let the oxidation number of sulfur be \( x \). Since there are 2 sulfur atoms, the equation becomes:
\[ 2x + 2(-1) = 0 \]
4. **Solve the equation**:
\[ 2x - 2 = 0 \\ 2x = 2 \\ x = +1 \]
5. **Conclusion**: Therefore, the oxidation number of sulfur in \( S_2F_2 \) is **+1**.

### Step 3: Determine the oxidation number of sulfur in \( H_2S \)

1. **Identify the compound**: \( H_2S \) consists of hydrogen and sulfur.
2. **Assign known oxidation number**: Hydrogen (H) has an oxidation number of +1.
3. **Set up the equation**: Let the oxidation number of sulfur be \( x \). The equation becomes:
\[ 2(+1) + x = 0 \]
4. **Solve the equation**:
\[ 2 + x = 0 \\ x = -2 \]
5. **Conclusion**: Therefore, the oxidation number of sulfur in \( H_2S \) is **-2**.

### Final Summary of Oxidation Numbers

- Oxidation number of sulfur in \( S_8 \): **0**
- Oxidation number of sulfur in \( S_2F_2 \): **+1**
- Oxidation number of sulfur in \( H_2S \): **-2**