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The conversion of molecules X to Y follo...

The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y ?

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The correct Answer is:
Rate of formation of `Y` will increase by 9 times
For second order kinetics, the rate law is `:`
`r_(1)=Rate_(1)=k[X]^(2) …..(i)`
If the concentration of `X` is increased to 3 times, `i.e., [3X], ` then rate `(r_(2))` will be
`r_(2)=k[3X]^(2)`
`9k[X]^(2) ….(ii)`
`:.(r_(2))/(r_(1))=(9k[X]^(2))/(k[X]^(2))=9`
`:.r_(2)=9r_(1)`
Thus, the rate of reaction will becomes 9 times. Hence, the rate of formation of `Y` will increases 9 times.
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