An organic compound (A) `(C_(10)H_(20))` on reductive ozonolysis gives `2-` methyl butanal. Based on this information, answer the following question.
The total number of stereoisomers possible for (A) is :

Options

A. 8
B. 7
C. 6
D. 4

Answer

To solve the problem, we need to determine the total number of stereoisomers possible for the organic compound (A) with the formula \( C_{10}H_{20} \), which on reductive ozonolysis gives 2-methylbutanal. Here’s a step-by-step breakdown:

### Step 1: Identify the structure of the product
The product of the ozonolysis is 2-methylbutanal. The structure of 2-methylbutanal can be represented as follows:

```
CH3
|
CH3-CH-CHO
|
CH2-CH3
```

### Step 2: Determine the structure of compound (A)
Since ozonolysis cleaves double bonds, compound (A) must have a structure that can yield two moles of 2-methylbutanal. The simplest structure that can achieve this is a compound with a double bond that, when cleaved, results in two identical aldehyde products.

A possible structure for compound (A) could be:
```
CH3
|
CH3-CH=CH-CH2-CH3
```
This structure has a double bond between the second and third carbon atoms.

### Step 3: Identify chiral centers in compound (A)
Next, we need to identify if there are any chiral centers in compound (A). A chiral center is typically a carbon atom that is bonded to four different groups.

In the structure of compound (A):
- The second carbon (C2) has the following groups: \( CH3, CH, CH2, H \) (which are different).
- The third carbon (C3) also has the following groups: \( CH3, CH2, CH, H \) (which are different).

Thus, both C2 and C3 are chiral centers.

### Step 4: Calculate the number of stereoisomers
The formula to calculate the number of stereoisomers based on the number of chiral centers (n) is given by:
\[ \text{Number of stereoisomers} = 2^n \]
Here, \( n = 2 \) (since we have two chiral centers).

Thus, the number of stereoisomers is:
\[ 2^2 = 4 \]

### Step 5: Consider geometric isomerism
Since compound (A) has a double bond, it can also exhibit geometric (cis/trans) isomerism. Each geometric isomer can also have the stereoisomers calculated previously.

For each of the 4 stereoisomers, there are 2 possible geometric isomers (cis and trans). Therefore, the total number of stereoisomers becomes:
\[ 4 \text{ (from chiral centers)} \times 2 \text{ (from geometric isomerism)} = 8 \]

### Final Answer
The total number of stereoisomers possible for compound (A) is **8**.

---