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Consider the following molecules . A:An...

Consider the following molecules .
`A`:Anti -pyridine -2-carboxaldoxime
`B`:syn pyridine -2-carboaxaldoxime
`C`: nickel -dimethyl glyoximate
`D` : o-nitrophenol
`E` : p-nitrophenol
`F` : p-salicylaldehyde
In which case chelate formation occurs ? .

A

`A,B`

B

`B,C`

C

`C,F`

D

`C` only

Text Solution

AI Generated Solution

The correct Answer is:
To determine in which of the given molecules chelate formation occurs, we need to analyze each molecule for the possibility of intramolecular hydrogen bonding, which is essential for chelation. ### Step-by-Step Solution: 1. **Analyze Anti-pyridine-2-carboxaldoxime (A)**: - Structure: In this molecule, the carboxaldoxime group is positioned in such a way that it can form a hydrogen bond with the nitrogen atom of the pyridine ring. - Conclusion: A six-membered chelate ring is formed due to this intramolecular hydrogen bonding. **Chelation occurs.** 2. **Analyze Syn-pyridine-2-carboxaldoxime (B)**: - Structure: Here, the carboxaldoxime group is on the same side as the pyridine nitrogen. - Conclusion: The spatial arrangement does not allow for effective intramolecular hydrogen bonding. **No chelation occurs.** 3. **Analyze Nickel-dimethylglyoximate (C)**: - Structure: This molecule has two oxime groups that can coordinate with the nickel atom, forming two chelate rings. - Conclusion: Intramolecular hydrogen bonding occurs, leading to chelation. **Chelation occurs.** 4. **Analyze o-Nitrophenol (D)**: - Structure: In this molecule, the hydroxyl (OH) group can form a hydrogen bond with the nitro (NO2) group due to their proximity. - Conclusion: This results in the formation of a stable chelate ring. **Chelation occurs.** 5. **Analyze p-Nitrophenol (E)**: - Structure: The hydroxyl (OH) group and the nitro (NO2) group are positioned far apart. - Conclusion: There is no possibility for intramolecular hydrogen bonding. **No chelation occurs.** 6. **Analyze p-Salicylaldehyde (F)**: - Structure: Similar to p-nitrophenol, the OH and CHO groups are also far apart. - Conclusion: There is no effective intramolecular hydrogen bonding. **No chelation occurs.** ### Summary of Chelation: - **Chelation occurs in molecules A (Anti-pyridine-2-carboxaldoxime), C (Nickel-dimethylglyoximate), and D (o-Nitrophenol).** - **No chelation occurs in molecules B (syn-pyridine-2-carboxaldoxime), E (p-nitrophenol), and F (p-salicylaldehyde).** ### Final Answer: Chelate formation occurs in molecules A, C, and D. ---

To determine in which of the given molecules chelate formation occurs, we need to analyze each molecule for the possibility of intramolecular hydrogen bonding, which is essential for chelation. ### Step-by-Step Solution: 1. **Analyze Anti-pyridine-2-carboxaldoxime (A)**: - Structure: In this molecule, the carboxaldoxime group is positioned in such a way that it can form a hydrogen bond with the nitrogen atom of the pyridine ring. - Conclusion: A six-membered chelate ring is formed due to this intramolecular hydrogen bonding. **Chelation occurs.** ...
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