Home
Class 11
CHEMISTRY
A binary of potassium (A) on heating wit...

A binary of potassium (A) on heating with sulphar, compound (B) is formed. (B) on reacting with `BaCI_(2)` gives a white precipitate (C ) which is insoluble in concentrated HCI. Indenfity (A), (B) and (C ).

Text Solution

Verified by Experts

`(A)+S overset(Delta)rarr (B)`
`(A)+BaCI_(2)rarr underset("White ppt.")(C )`
(A) is binary salt of potassium. (C ) is white ppt. which is insoluble in conc HCI.
`underset((A))(2KO_(2))+S overset(Delta)rarr underset((B))(K_(2)SO_(4))`
`underset((B))(K_(2)SO_(4)) + BaCI rarr 2KCI+ underset("Whuite ppt.")underset((C ))(BaSO_(4)darr)`
Hence, (A) is `KO_(2)` (potassium peroxide), (B) is `K_(2)SO_(4)` (potassium sulphate) and (C ) is `BaSO_(4)` (barium sulphate).
Promotional Banner

Topper's Solved these Questions

  • S-BLOCK GROUP 1 - ALKALI METALS

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 4.1 (Subjective)|24 Videos
  • S-BLOCK GROUP 1 - ALKALI METALS

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 4.1 (True/False)|1 Videos
  • S-BLOCK GROUP 1 - ALKALI METALS

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|8 Videos
  • REDOX REACTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives (Integers)|1 Videos
  • S-BLOCK GROUP 2 - ALKALINE EARTH METALS

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 5.1 Objective|2 Videos

Similar Questions

Explore conceptually related problems

The metallic salt (XY) is soluble in water. (a) When the aqueous soluble of (XY) is treated with NaOH solution, a white precipitate (A) is formed. In excess of NaOH solution, a white precipitate (A) is formed. In excess of NaOH solution, white precipitate (A) dissolves to form a compound (B) . When this solution is boiled with soild NH_(4) Cl , a precipitate of compound (C) is formed. (b) An aqueous solution on treatment with BaCl_(2) solution gives a white precipitate (D) white is insoluble in conc HCl . ( c) The metallic salt (XY) forms a double salt (E) with potassium sulphate. Identify (XY),(A),(B),(C),(D) and (E) .

Zinc on reaction with NaOH gives a salt (A) along with a gas (B). (A) on reaction with H_(2)S gas gives a white precipitate (C ). Identify (A), (B) and (C ).

A colourless mixture of two salts (A) and (B) (excess) is soluble in H_(2) O. (A) turns blue litmus red and (B) turns red litmus blue. (A) gives white precipitate with (B) , which dissolves in excess of (B) forming ( C).(A) when placed in atmosphere gives fumes and can form dimer. (A) gives white precipitate with NH_(4) Cl and NH_(4)OH which is soluble in (B) . Identify (A), (B) and (C) . Explain reactions.

When a colourless gas (A), which is poisonous and burns with blue flame, is passed through aqueous NaOH solution, gives a compound (B) . Compound (B) on heating gives (C ) . (C ) gives a white precipitate (D) with CaCl_(2) . Both (C ) and (D) decolourises KMnO_(4) . Identify (A) to (D) .

The gas librated , on heating a mixture of two salts with NaOH give sa reddish brown precipitate with an alkline solution of K_(2)HgI_(4) the aqeous solution of the mixture on treatment with BaCI_(2) gives awhite precipitate which is sparingly soluble with K_(2)Cr_(2)O_(7) and concentrated H_(2)SO_(4) red vapour of A are produced .The aqueous solution of the mixture gives a deep -blue colouration B with potassium ferrcyanide soluble identify the redicals in the gives mixture and write the balanced equation in the gives mixture and write the balanced equations for the formation of A and B

Alkanline earth metal nitrate (A) on heating decompose, leaving a solid residue (B) which goes into solution with dilute HCI . The solution of (B) gives a white precipitate (C ) is dissolved in dilute HCl and the solution is treated with potassium chromae to get yellow precipitate (D) . The solution (B) with dilute H_(2)SO_(4) also gives a white precipitate (E) insoluble in diute HCl and nitric acid. the precipitate (E) is a part of a white pigment lithopone. The compound (E) is

Alkanline earth metal nitrate (A) on heating decompose, leaving a solid residue (B) which goes into solution with dilute HCI . The solution of (B) gives a white precipitate (C ) is dissolved in dilute HCl and the solution is treated with potassium chromae to get yellow precipitate (D) . The solution (B) with dilute H_(2)SO_(4) also gives a white precipitate (E) insoluble in diute HCl and nitric acid. the precipitate (E) is a part of a white pigment lithopone. The solid residue (B) is

Alkanline earth metal nitrate (A) on heating decompose, leaving a solid residue (B) which goes into solution with dilute HCI . The solution of (B) gives a white precipitate (C ) is dissolved in dilute HCl and the solution is treated with potassium chromae to get yellow precipitate (D) . The solution (B) with dilute H_(2)SO_(4) also gives a white precipitate (E) insoluble in diute HCl and nitric acid. the precipitate (E) is a part of a white pigment lithopone. The yellow precipitate (D) is

Alkanline earth metal nitrate (A) on heating decompose, leaving a solid residue (B) which goes into solution with dilute HCI . The solution of (B) gives a white precipitate (C ) is dissolved in dilute HCl and the solution is treated with potassium chromae to get yellow precipitate (D) . The solution (B) with dilute H_(2)SO_(4) also gives a white precipitate (E) insoluble in diute HCl and nitric acid. the precipitate (E) is a part of a white pigment lithopone. The metal nitrate (A) is

An organic compound A’ with molecular formula C_(7)H_(7)NO reacts with Br_(2) /aqKOH to give compound B’, which upon reaction with NaNO_(2) & HCl" at "O^(@) C gives C’. Compound C’ on heating with CH_(3)CH_(2)OH gives a hydrocarbon D’. Compound B’ on further reaction with Br_(2) water gives white precipitate of compound E’. Identify the compound A, B, C, D&E, also justify your answer by giving relevant chemical equations.