`PCl_3, P_4 O_6` and `P_4 O_10, PCl_5` on hydrolysis gives respectivey.

Options

A. `H_3PO_3` and `H_3 PO_4`
B. `H_3 PO_4` and `H_3PO_3`
C. `(HPO_3)_n` and `H_4 P_2 O_7`
D. `H_4 P_2 O_7` and `(HPO_3)_n`

Answer

To solve the question regarding the hydrolysis products of \( PCl_3 \), \( P_4O_6 \), \( P_4O_{10} \), and \( PCl_5 \), we will analyze each compound step by step.

### Step 1: Hydrolysis of \( PCl_3 \)

**Reaction:**
\[ PCl_3 + 3H_2O \rightarrow H_3PO_3 + 3HCl \]

**Explanation:**
When phosphorus trichloride (\( PCl_3 \)) undergoes hydrolysis (reaction with water), it produces phosphorous acid (\( H_3PO_3 \)) and hydrochloric acid (\( HCl \)).

### Step 2: Hydrolysis of \( P_4O_6 \)

**Reaction:**
\[ P_4O_6 + 6H_2O \rightarrow 4H_3PO_3 \]

**Explanation:**
When tetraphosphorus hexoxide (\( P_4O_6 \)) is hydrolyzed, it yields four moles of phosphorous acid (\( H_3PO_3 \)).

### Step 3: Hydrolysis of \( P_4O_{10} \)

**Reaction:**
\[ P_4O_{10} + 4H_2O \rightarrow 4H_3PO_4 \]

**Explanation:**
Tetraphosphorus decoxide (\( P_4O_{10} \)) reacts with water to produce four moles of phosphoric acid (\( H_3PO_4 \)).

### Step 4: Hydrolysis of \( PCl_5 \)

**Reaction:**
\[ PCl_5 + 4H_2O \rightarrow H_3PO_4 + 5HCl \]

**Explanation:**
Phosphorus pentachloride (\( PCl_5 \)) on hydrolysis produces phosphoric acid (\( H_3PO_4 \)) and hydrochloric acid (\( HCl \)).

### Final Summary of Hydrolysis Products

- Hydrolysis of \( PCl_3 \) gives \( H_3PO_3 \).
- Hydrolysis of \( P_4O_6 \) gives \( H_3PO_3 \).
- Hydrolysis of \( P_4O_{10} \) gives \( H_3PO_4 \).
- Hydrolysis of \( PCl_5 \) gives \( H_3PO_4 \).

### Conclusion

Thus, the hydrolysis products are:
- From \( PCl_3 \) and \( P_4O_6 \): \( H_3PO_3 \)
- From \( P_4O_{10} \) and \( PCl_5 \): \( H_3PO_4 \)

The correct answer is \( H_3PO_3 \) and \( H_3PO_4 \).