Chlorine reacts with excess of ammonia to form.

Options

A. `NH_4 Cl`
B. `N_2 + HCl`
C. `N_2 + NH_4 Cl`
D. `N_2 + NCl_3`

Explanation

To solve the question "Chlorine reacts with excess of ammonia to form," we will follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are chlorine (Cl₂) and ammonia (NH₃).

### Step 2: Understand the Reaction
Chlorine (Cl₂) is a halogen that acts as a Lewis acid because it can accept electrons. Ammonia (NH₃) acts as a Lewis base because it can donate a lone pair of electrons.

### Step 3: Write the Reaction
When chlorine reacts with ammonia, the chlorine gets reduced and the nitrogen in ammonia gets oxidized. The overall reaction can be represented as:
\[ \text{Cl}_2 + \text{NH}_3 \rightarrow \text{N}_2 + \text{Cl}^- \]

### Step 4: Consider Excess Ammonia
Since the question specifies that there is excess ammonia, the chlorine ions (Cl⁻) formed will react with the excess ammonia to form ammonium chloride (NH₄Cl).

### Step 5: Write the Complete Reaction
Taking into account the excess ammonia, the complete balanced reaction can be written as:
\[ \text{Cl}_2 + 6 \text{NH}_3 \rightarrow \text{N}_2 + 6 \text{NH}_4\text{Cl} \]

### Step 6: Finalize the Products
From the balanced equation, we can see that the products of the reaction are nitrogen gas (N₂) and ammonium chloride (NH₄Cl).

### Final Answer
Thus, the products formed when chlorine reacts with excess ammonia are:
\[ \text{N}_2 + 6 \text{NH}_4\text{Cl} \]